erfc with complex number
18 ビュー (過去 30 日間)
古いコメントを表示
Hi all
I want to compute erfc(.) of a complex number. How can I do that? Is there any way to use erfc(.) of matlab?
0 件のコメント
採用された回答
Matt Fig
2011 年 5 月 10 日
14 件のコメント
Walter Roberson
2020 年 2 月 5 日
To check, you have
d2=(8*m^3/2);
Is it possible that that should be
d2=(8*m^(3/2));
The current expression would be equivalent to the clearer
d2=4*m^3;
Or even 8/2 instead of 4 if that somehow made documentation sense. With the /2 where it is and with the leading multiplier already even, people are going to wonder.
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Calculus についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!