function P = Fillter(K)
dem=0;
%F=zeros(10001,2);
F(1,1)=K(1,1);
F(1,2)=K(1,2);
t=length(K(:,1));
for i=2:1:t
if (K(i,1)~=K(i-1,1))
F(i-dem,1)=K(i,1); F(i-dem,2)=K(i,2);
else
dem=dem+1;
end
end
P=F;
end
Line : F(1,1)=K(1,1); Not enough input arguments.
How to fix that?

 採用された回答

the cyclist
the cyclist 2021 年 1 月 5 日

0 投票

How are you calling the function? If you call it like this ...
Fillter()
then you will get that error because Fillter is expecting one input, and it is receiving zero inputs.

2 件のコメント

Stefania Rauta
Stefania Rauta 2021 年 1 月 6 日
that's not the problem :(
the cyclist
the cyclist 2021 年 1 月 6 日
You didn't answer the question, though. How are you calling the function? Can you upload a complete set of code we can run, that gives the error? Because if I call it as follows
Fillter([1 2 3 4])
then the code runs to completion with no error.

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