How can I plot these 3 ode45 functions in 1 graph?

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Carey n'eville
Carey n'eville 2020 年 12 月 27 日
コメント済み: Star Strider 2020 年 12 月 28 日
Hello dear friends I have 3 codes which are different from each other with TH values and tspans ( for first TH=10 and tspan=[0 10], for second TH=20 & tspan=[0 20] and for the third one TH=40 & tspan=[0 40]). I need to plot all these 3 functions in one graph. At first step If it is possible, can you show me combining these three in one code and plot in same graph? Could you help me please? Codes are given below in order:
First:
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
Ks=150;
Y=0.5;
XS0=[2, 1000];
tspan = [0 10];
[t,XS]=ode45(@BSfunction, tspan, XS0);
function dXSdt=BSfunction(TH,XS)
X = XS(1); S = XS(2);
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
V=20;
TH=10;
ko=0.2;
kd=0.01;
Ks=150;
Y=0.5;
S=S0-(ko/Y)*X0*TH;
biomassgrowth=((ko*S*X)/(Ks+S))-(kd*X);
substratutilize = -((ko/Y)*X0);
dXSdt = [biomassgrowth; substratutilize];
end
Second:
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
Ks=150;
Y=0.5;
XS0=[2, 1000];
tspan = [0 20];
[t,XS]=ode45(@BSfunction, tspan, XS0);
function dXSdt=BSfunction(TH,XS)
X = XS(1); S = XS(2);
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
V=20;
TH=20;
ko=0.2;
kd=0.01;
Ks=150;
Y=0.5;
S=S0-(ko/Y)*X0*TH;
biomassgrowth=((ko*S*X)/(Ks+S))-(kd*X);
substratutilize = -((ko/Y)*X0);
dXSdt = [biomassgrowth; substratutilize];
end
Third:
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
Ks=150;
Y=0.5;
XS0=[2, 1000];
tspan = [0 40];
[t,XS]=ode45(@BSfunction, tspan, XS0);
function dXSdt=BSfunction(TH,XS)
X = XS(1); S = XS(2);
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
V=20;
TH=40;
ko=0.2;
kd=0.01;
Ks=150;
Y=0.5;
S=S0-(ko/Y)*X0*TH;
biomassgrowth=((ko*S*X)/(Ks+S))-(kd*X);
substratutilize = -((ko/Y)*X0);
dXSdt = [biomassgrowth; substratutilize];
end

採用された回答

Star Strider
Star Strider 2020 年 12 月 27 日
The lines are not easily distinguishable.
Try this:
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
Ks=150;
Y=0.5;
XS0=[2, 1000];
THv = [10 20 40];
for k = 1:numel(THv)
tspan = [0 THv(k)];
[t{k},XS{k}]=ode45(@(t,XS)BSfunction(t,XS,THv(k)), tspan, XS0);
end
figure
LineStl = {'-','-.','--'};
hold on
for k = 1:numel(THv)
semilogy(t{k}, XS{k}, 'LineWidth',1.5, 'DisplayName', ['TH = ',num2str(THv(k))], 'LineStyle',LineStl{k})
end
hold off
grid
% lgdstr = compose('TH = %d', THv);
legend
figure
for k = 1:numel(THv)
subplot(numel(THv), 1, k)
plot(t{k}, XS{k}, 'LineWidth',1.5)
title(compose('TH = %d', THv(k)));
grid
end
function dXSdt=BSfunction(t,XS,TH)
X = XS(1); S = XS(2);
X0=2;
Sin=1000;
So=0;
S0=So+Sin;
V=20;
% TH=10;
ko=0.2;
kd=0.01;
Ks=150;
Y=0.5;
S=S0-(ko/Y)*X0*TH;
biomassgrowth=((ko*S*X)/(Ks+S))-(kd*X);
substratutilize = -((ko/Y)*X0);
dXSdt = [biomassgrowth; substratutilize];
end
The first figure plots them all on one axes, the second figure plots them each as separate subplots.
  2 件のコメント
Carey n'eville
Carey n'eville 2020 年 12 月 28 日
編集済み: Carey n'eville 2020 年 12 月 28 日
Thank you so much!!!!! I guess this is enough for me
Star Strider
Star Strider 2020 年 12 月 28 日
As always, my pleasure!

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