what is wrong?

1 回表示 (過去 30 日間)
Sahab
Sahab 2011 年 5 月 7 日
it should show answer of -30,why it show -10?what is wrong?
x=[33,11,33,11,22,33,11];
r4penalty=0;
r3penalty=0;
r2penalty=0;
r1penalty=0;
penalty=0;
for ii = 1:size(x,1)
c = 1;
Y = x(ii,:)==33;
while c <= length(x)-1
if Y(c)
if x(ii,c+1)==11
r4penalty=-10;
c= c + 1;
elseif Y(c+1:c+2) % Three in a row. (33,33,33)
r3penalty=-30;
c = c + 4;
elseif x(ii,c+1)==33 % Two in a row.(33,33,11)
r2penalty=-20;
c = c + 3;
elseif x(ii,c+1)==11 % Just one 33. (33,11)
r1penalty=-10;
c = c + 2;
elseif x(ii,c+1)==22 % pattern 33,22
c = c + 1;
end
else
c = c + 1;
end
end
penalty(ii,1)=r1penalty+r2penalty+r3penalty+r4penalty
end
did somebody know?

採用された回答

Amir Hamzah UTeM
Amir Hamzah UTeM 2011 年 5 月 7 日
try do this,
total=0;
penalty=0;
for ii = 1:size(x,1)
c = 1;
Y = x(ii,:)==33;
while c <= length(x)-1
if Y(c)
if x(ii,c+1)==11
penalty1=-10;
total(ii,1)=total+penalty1
c= c + 1;
elseif Y(c+1:c+2) % Three in a row. (33,33,33)
penalty2=-30;
total(ii,1)=total+penalty2
c = c + 4;
elseif x(ii,c+1)==33 % Two in a row.(33,33,11)
penalty3=-20;
total(ii,1)=total+penalty3
c = c + 3;
elseif x(ii,c+1)==11 % Just one 33. (33,11)
penalty4=-10;
total(ii,1)=total+penalty4
c = c + 2;
elseif x(ii,c+1)==22 % pattern 33,22
c = c + 1;
end
else
c = c + 1;
end
end
total(ii,1)=total
end

その他の回答 (1 件)

Oleg Komarov
Oleg Komarov 2011 年 5 月 7 日
The vectorized solution to your problem:
x = [33,11,33,11,22,33,11];
% Find the 33s that are immediately before 22
bon = nnz(strcmp(x,[33 22]));
% Count the total number of 33
mal = nnz(x == 33);
% Total penalty = -(total33 - 33before22) * single penalty
penalty = -(mal-bon)*10;
  1 件のコメント
Andrei Bobrov
Andrei Bobrov 2011 年 5 月 7 日
or
t = x==33;
penalty= -(sum(t) - sum(x(find(t)+1)==22))*10;

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