How to calculate the determinant of a symbolic matrix 5x5
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Suppose we have a symmetric,real matrix,K 5x5: K = [0 0 0 F 0; 0 0 F E 0;0 F E D 0;F E D C 0;0 0 0 0 A]
A,C,D,E,F are matrices (their size does not matter to me). How can i say to matlab to consider these entries as matrices and thereafter calculating the determinant of K ?
1 件のコメント
Walter Roberson
2013 年 3 月 31 日
Are A, C, D, E, F each square matrices? Are they the same size as each other? And should the zeroes be implicitly expanded to match the size of the matrices?
e.g., if each matrix is nxn and Z represents zeros(n,n) then you have K = [Z Z Z F Z; Z Z F E Z] and so on?
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Ahmed A. Selman
2013 年 3 月 31 日
I don't think it is possible to concatenate a matrix such as K if A-F have sizes > (1,1), thus no value of the determinant exist. This is because if e.g., [E] exists, then K(1,:)=[0 0 0 F 0] and K(2,:)=[0 0 F E 0] must be the same size, hence (E = [E], e.f., E is 1 by 1 matrix).
If the matrix K do exist, please explain further what is the shape of A-F sub matrices.
Otherwise just use the regular concatenation functions (cat, vertcat or horzcat) to construct K from A-F submatrices, and det(K) to find the determinant.
2 件のコメント
Walter Roberson
2013 年 3 月 31 日
looks like it might be det(F)^4*det(A) with no component of C, D, or E.
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