derive new variable with random float values using for loop

3 ビュー (過去 30 日間)
Arturo Jr. Ongkeko
Arturo Jr. Ongkeko 2020 年 12 月 12 日
コメント済み: Arturo Jr. Ongkeko 2020 年 12 月 13 日
Hi, I am trying to derive a new variable with random float values using for loop. Tried using randn.
for i=1:length(hosp_yn_coded)
if (hosp_yn_coded(i)==1)
los_total(i)=randn([0 2],1,1) % must be float bet 0-2 e.g. 0.1,0.2,0.4,1.4,1.2
else
los_total(i)=randn([0 1],1,1) % must be float bet 0-2 e.g. 0.1,0.2,0.4,1.4,1.2
end
end
Thanks so much!

採用された回答

Jeff Miller
Jeff Miller 2020 年 12 月 13 日
Despite your comments, I guess you want 0-1 for the second option, not 0-2.
I guess you want all numbers in the range to be equally likely, so randn is not the right choice.
I wouldn't use a for loop here, but you can if you want:
for i=1:length(hosp_yn_coded)
if (hosp_yn_coded(i)==1)
los_total(i)=2*rand; % rand gives 0-1, so 2*rand is 0-2
else
los_total(i)=rand;
end
end
  1 件のコメント
Arturo Jr. Ongkeko
Arturo Jr. Ongkeko 2020 年 12 月 13 日
Hi, Jeff! Thanks so much. I am trying to be comfortable with for-loops so this is like a practice for me.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by