Creating a solid/surface of revolution from discrete data?
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Hi, I have 3 sets of discrete data from an airjet experiment, which roughly form velocity profiles when plotted: http://oi47.tinypic.com/i1b0v5.jpg
I now want form a solid/surface of rotation about y=0 for that graph (rotated only 180deg), and a 3D plot of it. How do I do that?
I've tried the cylinder function, but how do I change the axis of rotation and how can I tell it to 'only rotate through 180 degrees, not 360'?
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Doug Hull
2013 年 3 月 29 日
The profile you give represents the radius. Set it to whatever you want. Then you can translate the surface by adding a constant in each direction.
As for rotating only partial, you could filter the data that comes out of cylinder, throwing out the parts you do not want.
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Kiran Sagar
2013 年 3 月 29 日
First of all your velocity profile is not symmetric about y=0, so if you rotate that graph by 180, you will not get a closed surface of rotation. Technically, it should not be called as a surface of rotation.
If you have velocity data in one plane only, then it is better not to represent the same profile over the whole angular domain (in 3D).
But if you have velocity profile in different planes, then you can use the "sftool" to get the best 3D fit of the points. More the no of planes, better will be the fit.
AliDomi
2016 年 12 月 16 日
You might find this approach useful. Let b be a symmetric curve with odd number of samples.
[rx,ry]=meshgrid( -order/2:order/2 , -order/2:order/2 );
r = hypot( rx , ry );
halfb = b((length(b)-1)/2 + 1 : end );
vq = interp1( 0:(length(halfb)-1) , halfb , r(:) , 'linear' , 0 );
W=r; W(:)=vq;
Then W is the revolved surface of b, note r is the distance from the center of the grid.
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