Sort a matrix without using the sort function

To study, I am trying to sort a matrix using for loops. I used a template I had for finding a max.

[row,column]=size(a);
sortmx=zeros(size(a));

for n=1:column
    mx=a(1,n);
    for p=2:row
        if a(p,n)>mx
            mx=a(p,n); 
        else
            mx=a(p-1,n);
        end
    end
    sortmx(n,p)=mx
end

Answer 1

[Paulo Silva]

[row,column]=size(a);
  for nc=1:column
      for nr=1:row
          [C,I]=max(a(nr:row,nc));
          b=a(nr,nc);
          a(nr,nc)=C;
          a(I(1)+nr-1,nc)=b;
      end
  end

[Roland]

I am failing at getting anything correct, how would order each number in an individual column rather than find one value?

[Matt Fig]

Did you search MATLAB Answers first? I found at least two identical questions from past posters....

This must be a popular homework question indeed!