Solving an equation involving variables as column vector using 'solve' function
5 ビュー (過去 30 日間)
古いコメントを表示
%arrayTest
A=[1;2; 12; 3; 3; 4]
b= [1; 2; 12; 3; 3; 4]
sym tx1
sym tS
x1 = [1:numel(A)]; %row vector
tx1 = transpose(x1) %column vector
S=[1:numel(A)]; %row vector
tS=transpose(S) %column vector
for i = transpose(1:numel(A)) %intializing loop from 1 till the number of rows of A
for j=1 %number of column = 1
tS(i,j) = solve( 1.*b + x1.*A == 0, tx1(i,j)) %solve equation
end
end
%Error
%Check for missing argument or incorrect argument data type in call to function 'solve'.
%Error in TEST_array (line 28)
%tS(i,j) = solve( 1.*b + tx1.*A == 0, tx1(i,j))
Dear Experts!!:)
I am trying to solve an equation containing variables as column vectors. I have declared the symbolic variables and have tried to use the function solve.
I keep getting this error as an incorrect arugument data type for function solve!!
Can someone help me out with this error!??
And also, how can i create and display an array which stores all the solutions of the solve function??
2 件のコメント
Walter Roberson
2020 年 12 月 8 日
tS(i,j) = solve( 1.*b + x1.*A == 0, tx1(i,j)) %solve equation
tx1 is numeric. Why are you passing it to solve()?
回答 (1 件)
Ashish Mishra
2020 年 12 月 14 日
Hi Sanjeet
You want to solve the equation for tx1(i,j) but it is a constant array (from 6th line).
Moreover in your equation , everything is constant.
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Symbolic Math Toolbox についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!