Laplace transform not found.
10 ビュー (過去 30 日間)
古いコメントを表示
I am trying to compute the Laplace transform of a known function. I have replicated the code shown below in Mathematica and it works fine, but I am unsure as to why it is not working in Matlab. The result I get is just laplace (some expression).
clearvars
close all
syms G w0 wc wk tau s C
a(tau) = int(wk^3*exp(-1i*(wk-w0)*tau), wk, 0, wc);
corr(tau) = (G/(w0^3))*(a(tau));
F(s) = laplace(corr(tau),tau,s);
C(s) = solve(s*C-1==-F(tau)*C,C);
2 件のコメント
Walter Roberson
2020 年 12 月 3 日
編集済み: Walter Roberson
2020 年 12 月 3 日
How are you doing the transform in Mathematica? Wolfram Alpha says it is invalid.
https://www.wolframalpha.com/input/?i=laplace+transform&assumption=%7B%22F%22%2C+%22LaplaceTransformCalculator%22%2C+%22transformfunction%22%7D+-%3E%22%28G*%28%286*exp%28tau*w0*sqrt%28-1%29%29%29%2Ftau%5E4+%2B+%28exp%28tau*w0*sqrt%28-1%29%29*exp%28-tau*wc*sqrt%28-1%29%29*%28tau%5E3*wc%5E3*sqrt%28-1%29+%2B+3*tau%5E2*wc%5E2+-+tau*wc*6*sqrt%28-1%29+-+6%29%29%2Ftau%5E4%29%29%2Fw0%5E3%22&assumption=%7B%22F%22%2C+%22LaplaceTransformCalculator%22%2C+%22variable1%22%7D+-%3E%22tau%22&assumption=%7B%22C%22%2C+%22laplace+transform%22%7D+-%3E+%7B%22Calculator%22%7D&assumption=%7B%22F%22%2C+%22LaplaceTransformCalculator%22%2C+%22variable2%22%7D+-%3E%22s%22
回答 (1 件)
Walter Roberson
2020 年 12 月 3 日
The wk^3*exp(x*tau) is getting integrated to include a /tau^4 term -- the general pattern wk^n*exp(...*tau) integrates to something that divides by tau^(n+1)
And that is leading to a problem with the laplace. You do not have compensating tau^4 in your numerator, and
syms t s
laplace(1/t, t, s)
which is to say that the laplace transform of division by the variable being transformed is not being processed. That is because the transform does not exist.
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!