Assign multi-dimension array to data structure array without for-loop

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Daehung Kang
Daehung Kang 2011 年 5 月 4 日
I want to remove for-loop in order to assign array to data structure array.
S(1:3) = struct('a', zeros(3,3));
tmp = random('Normal', 0, 1, 3, 3, 3);
for ie = 1:3
S(ie).a = tmp(:,:,ie);
end
Here, I want to obtain S(:).a without for-loop. In addition, S(:).a is updated sometimes.
Many Thanks!
  1 件のコメント
Jan
Jan 2011 年 5 月 4 日
The FOR loop is fine and efficient. Why do you want to remove it?

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回答 (2 件)

Matt Fig
Matt Fig 2011 年 5 月 4 日
For example:
clear T S
T = rand(3,3,3);
S(1:3) = struct('a', mat2cell(T,3,3,[1 1 1]));
isequal(T(:,:,2),S(2).a) % just to check...

Daehung Kang
Daehung Kang 2011 年 5 月 4 日
If I have other fields in S(:), it should have following error. dissimilar structure.
Also, I want to update S(:).a sometimes, not declaration of structure field.
Thanks again.
  2 件のコメント
Oleg Komarov
Oleg Komarov 2011 年 5 月 4 日
The you can't do it w/o a loop.
Matt Fig
Matt Fig 2011 年 5 月 4 日
These are details you left out of your original question, and they change the outcome. I did, however, answer your original question...

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