Square Root Complex Numbers
29 ビュー (過去 30 日間)
古いコメントを表示
Hi
I'm new to Matlab. I have a matrix of data for example 1.04,-5.84,-5.84,8.54 etc. As you can see its a mixture of positive and negative values. I have to square root all the numbers and then add the square root up.
I get an output like this: 0 + 0.2572i 1.4758 0 + 1.0258i 0 + 1.0297i .... etc
How can I add these up because when I do the sum total is displayed like so: 24.1589 +25.8258i I was expecting a real number such as 25.0414 why is it formatted like this. I am new to matlab so not sure what I need to do, works fine if my data has no negative numbers so I assume it's to do with that.
Thanks
3 件のコメント
Youssef Khmou
2013 年 3 月 9 日
real parts are summed separately from imaginary parts , if you want add both Real and Imag sumsthen try :
r=rand(10);
p=sqrt(r);
S=sum(real(p(:)))+sum(imag(p(:)));
回答 (2 件)
Youssef Khmou
2013 年 3 月 9 日
hi Josh,
the square root of <0 number is complex number , if you only want the real part use "real" function, but if you want imaginary part, use "imag" function, and for the modulus you can use "abs" function , example :
r=randn(10);
p=sqrt(r);
Real_part=sum(real(p(:)));
Imag_part=sum(imag(p(:)));
Modul_part=sum(abs(p(:)));
0 件のコメント
Walter Roberson
2013 年 3 月 10 日
編集済み: Walter Roberson
2013 年 3 月 10 日
To get the results you indicate you want (which are not the results one would normally want when taking the square roots of negative numbers),
sum(sqrt(r(r>0))) - sum(sqrt(-r(r<0)))
Remember, sqrt(-A) is not -sqrt(A) but is instead 1i * sqrt(A) where 1i indicates sqrt(-1)
5 件のコメント
参考
カテゴリ
Help Center および File Exchange で Image Processing Toolbox についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!