How fill a part of 3D array with decreasing values?
3 ビュー (過去 30 日間)
古いコメントを表示
Dear all,
I have a 3D array and I just want to fill a buck of this array with decreasing values, with step i've chosen. The values would decrease only in one direction, and constant on the two others.
For instance i have this : >> N=10; >> X=zeros(N,N,N); >> X(:,:,1:10)=20:-2:2; ??? Assignment has fewer non-singleton rhs dimensions than non-singleton subscripts
Could somebody help me with the syntax please?
Thanks in advance.
Alexandre.
0 件のコメント
採用された回答
Carlos
2013 年 3 月 8 日
I think you are trying to do something like this
>> a=20:-2:2;
>> for i=1:10
for j=1:10
X(i,j,1:10)=a(1:10);
end
end
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Matrix Indexing についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!