how to use datetime ?

2 ビュー (過去 30 日間)
pruth
pruth 2020 年 11 月 19 日
編集済み: Ananthi Jegan 2020 年 11 月 19 日
I am not sure what am i doing wrong here.
jday = '190608' % year month day
datetime(jday, 'InputFormat', 'yyMMDD')
this should give me an out put as 8-june-2019
but instead of that it gives me 08-Jan-2019 ! why is this happening ??
i have another question ! i have a time in this format 190608.347009447 - 'yymmdd.ffffffff', 'ffffffff' is the fractional part of the day.
to read this i am using this code !
inputtime = '190608.347009447';
jday = inputtime(1:6);
date(i) = datetime(jday, 'InputFormat', 'yyMMDD') + days(mod(str2double(inputtime), 1))
it gives me an error !!

採用された回答

Ananthi Jegan
Ananthi Jegan 2020 年 11 月 19 日
編集済み: Ananthi Jegan 2020 年 11 月 19 日
For your first question, you have to use the InputFormat as 'yyMMdd' instead of 'yyMMDD'
datetime(jday,'InputFormat','yyMMdd')
Changing the above InputFormat also helps in correcting the second error as well; and to get the datetime including time values as follows
inputtime = '190608.347009447';
jday = inputtime(1:6);
datetime(jday, 'InputFormat', 'yyMMdd') + days(mod(str2double(inputtime), 1))
I hope this helps to correct the errors and to get the results as expected.
  1 件のコメント
pruth
pruth 2020 年 11 月 19 日
yes sir, it worked perfectly ! thank you !

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeArray Geometries and Analysis についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by