It shows Error in my GUI...

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Lalit Patil
Lalit Patil 2013 年 2 月 21 日
Error= num2str(err)
if Error(1) > 0.10000
L = 'Fail.';
set(handles.text15,'string',L);
else
L = 'Pass';
set(handles.text15,'string',L);
end
This is my program -
First In command window i am getting this answer in two lines and i want to use second, but every time it will not give two answers, but whatever the number is, i want to use last,
Error =
0.091683 0.085897
But in GUI it always shows Fail.. Why..?

回答 (1 件)

Walter Roberson
Walter Roberson 2013 年 2 月 21 日
You are converting "err" to a string, and then comparing the string to the numeric value 0.10000. Why are you not comparing err instead of Error?
  3 件のコメント
Image Analyst
Image Analyst 2013 年 2 月 23 日
編集済み: Image Analyst 2013 年 2 月 23 日
That doesn't make sense. What Walter asked is why you don't simply do this:
if err(2) > 0.10000
L = 'Failed';
else
L = 'Passed';
end
set(handles.text15,'string',L);
Lalit Patil
Lalit Patil 2013 年 2 月 23 日
編集済み: Lalit Patil 2013 年 2 月 23 日
If i tale only
err > 0.10000
then it takes first value of err and then works correctly, but
Currently i know in answer of err that there are two values so i can take
err(2) > 0.10000
But each time i will not know. Some time there will be 3 values or some time there will be 4.. So, i want to do such that whatever the number of values, i have only to take last..
So, i may have to apply any counting mechanism or any thing else and how..?

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