フィルターのクリア

population growth for this problem matlab

29 ビュー (過去 30 日間)
marie
marie 2013 年 2 月 20 日
編集済み: per isakson 2017 年 8 月 22 日
The population of a certain country is 50 million and is expected to double in 20 years. Calculate the population 5, 10, and 15 years from now by defining a vector t with 3 elements and using element-by-element calculations. Population growth can be modeled by the equation p=p02^t/d where P is the population at time t, 0 P is the population at t = 0, and d is the doubling time.
so the equation is p=p02^t/d
I have d=ln(2)/20=0.035 then ln(2)/0.035
p=50000000*exp(d/t)
is that righ?
  4 件のコメント
Youssef  Khmou
Youssef Khmou 2013 年 2 月 21 日
編集済み: Youssef Khmou 2013 年 2 月 21 日
the population is 50 e+6 now and expected to double in 20 years, so 100 millions next 20 years ? "double" like x2 ? anyway it means increasing but your last equation is decreasing, at least change the last eq to : exp(t/d) .
Subrata Paul
Subrata Paul 2017 年 8 月 22 日
編集済み: per isakson 2017 年 8 月 22 日
Try this...
%Taking the inputs
p0 = input('Enter the population at time(0): ');
d = input('Enter time in which population will be double: ');
%Have to calculate at 5,10,15 years
t = [5 10 15];
l = length(t);
%Population
p = ones(1,3)
for i = 1:l
temp = pow2( t(i) / d);
x(i) = floor( p0 * temp);
end
%Output
'The populations at 5,10 and 15 years are gradulally '
x
%Drawing graph
plot(t,x,'p-b');
xlabel('Years(t)'); ylabel('Population');
title('Population at different years');

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by