how to disable the picture

Hi, every time I run the following code, a figure is generated. How can I disable it?
Thanks.
a0 = 0.05; a1 = 0.1; b1 = 0.85;
nu = randn(2300,1);
epsi = zeros(2300,1);
h = zeros(2300,1);
for i=2: 2300
h(i) = a0 + a1 * epsi(i-1)^2 + b1 * h(i-1) ;
epsi(i) = nu(i) * sqrt(h(i));
end
yt = zeros(2300,1);
for i=1: 2300
yt(i) = epsi(i)*epsi(i);
end
order = 15;
m = arx(yt, order);

7 件のコメント

Image Analyst
Image Analyst 2013 年 2 月 18 日
編集済み: Image Analyst 2013 年 2 月 18 日
I ran it up through the arx() function and it produced no figure. It must get produced in arx(). What is that function? Is it in some toolbox that you forgot to list in the Products below, like the MATLAB coder which you listed in the Tags?
dav
dav 2013 年 2 月 18 日
編集済み: Image Analyst 2013 年 2 月 19 日
Sorry a part of the code was missing in my first question
here's the code again.. It is the corr function of the residuals
a0 = 0.05;
a1 = 0.1;
b1 = 0.85;
nu = randn(2300,1);
epsi = zeros(2300,1);
h = zeros(2300,1);
for i=2: 2300
h(i) = a0 + a1 * epsi(i-1)^2 + b1 * h(i-1) ;
epsi(i) = nu(i) * sqrt(h(i));
end
yt1 = zeros(2300,1);
for i = 1 : 2300
yt1(i) = epsi(i)*epsi(i);
end
yt=yt1(1301:2300);
order = 15;
m = arx(yt1, order);
r = resid([yt1(1:order);yt1], m);
r = r(order+1:end);
Walter Roberson
Walter Roberson 2013 年 2 月 19 日
I do not understand what this question has to do with the Mathworks product that converts MATLAB code to C or C++ code? You tagged this with "MATLAB Coder" ?
Image Analyst
Image Analyst 2013 年 2 月 19 日
And I still don't get a spurious figure, or any figure at all. It runs up until the call to arx() and then bombs. Again, what toolbox is arx() in? I guess it doesn't matter though since whatever toolbox it's in, I don't have it, but others who might want to help you might want to know this so they don't waste their time too. Or is arx() some custom m-file you wrote?
Walter Roberson
Walter Roberson 2013 年 2 月 19 日
arx() appears to be in Systems Identification but that does not appear to me to plot anything.
dav
dav 2013 年 2 月 19 日
I am sorry its in the system identification tool box
Walter Roberson
Walter Roberson 2013 年 2 月 19 日
Have you tried using the debugger and stepping through the code to find out which command is generating the plot ?

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回答 (2 件)

Youssef  Khmou
Youssef Khmou 2013 年 2 月 19 日

1 投票

hi,
your code does not produce any figure,
but if you want, you can add the following at the end of your code :
close;
Rajiv Singh
Rajiv Singh 2013 年 2 月 19 日

1 投票

It is the RESID command that is bringing up the plot. It belongs to System Identification Toolbox. To make it work as documented (no figures when called with output arguments), use an IDDATA object to represent the data, as in:
r = resid(iddata([yt1(1:order);yt1]), m);
Calling RESID with double vector representing data is supported for backward compatibility. However, in this mode, the plot also gets shown since this was the behavior in the past before IDDATA object was introduced (I believe in ver 5).

1 件のコメント

dav
dav 2013 年 2 月 21 日
編集済み: dav 2013 年 2 月 21 日
thnks. but the problem is that now I dont get the residuals either... can u fix that please?
I need to get the residuals in to a vector (r). But when i type r at the command prompt I dont see the residuals.
thanks

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dav
2013 年 2 月 18 日

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