How to write a symbolic function array?
1 回表示 (過去 30 日間)
古いコメントを表示
function f=g5(x)
syms q b x
q=[6 7 1;7 11 2;1 2 22]
b=[-1;2;3]
x=transpose(sym('x',[1 3]))
f=1/2*transpose(x)*q*x+transpose(b)*x-2
end
This is my writing function
clc;
clear;
%%gradient descent
syms w
w=[2;2;6]
for i=1:30
w=w-5*gradient(g5(w))
%%if norm(gradient(g5(w)))>0.01
%%break
%%end
display(w)
end
This is the variable I setted trying to find the solution of the function. But the outcome is
w =
152 - 1050*x2 - 150*x3 - 900*x1
- 1050*x1 - 1650*x2 - 300*x3 - 298
- 150*x1 - 300*x2 - 3300*x3 - 444
I want to insert [2;2;6] into [x1;x2;x3] to get the value of the function. But it seems symbolic variables defined cannot be taken as parameters. Is there any way to change it into independent variables?
6 件のコメント
Walter Roberson
2020 年 11 月 6 日
w=[2;2;6];
g5(w)
function f=g5(x)
q = [6 7 1;7 11 2;1 2 22];
b = [-1;2;3];
f = 1/2*x'*q*x + b'*x - 2;
end
Looks okay to me.
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