sorting Matrix in two coum matrix

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Liaquat Ali
Liaquat Ali 2013 年 2 月 5 日
Hallo every body have this matrix as
-4.1060 -0.0020 -4.1060 -0.0010 -4.1090 -0.0010
-3.9950 3.2950 -3.9950 3.2960 -4.0030 3.2930
-3.9940 3.2940 -3.9970 3.2970 -4.0010 3.2940
-4.1060 -0.0020 -4.1080 0 -4.1060 -0.0020
-4.1070 0 -4.1070 -0.0020 -4.1090 -0.0010
-3.9960 3.2930 -3.9970 3.2970 -4.0030 3.2960
-3.9970 3.2930 -4.0010 3.3050 -4.0020 3.2950
-4.1060 -0.0020 -4.1060 0 -4.1080 -0.0010
-4.1070 0 -4.1060 0 -4.1080 0
-3.9860 3.2860 -3.9970 3.2970 -4.0030 3.2950
-3.9950 3.2950 -3.9970 3.2970 -4.0030 3.2950
-4.1060 -0.0010 -4.1060 -0.0010 -4.1070 0
-4.1060 -0.0010 -4.1080 0 -4.1090 0.0010
-3.9980 3.2970 -3.9990 3.2970 -4.0030 3.2950
-3.9950 3.2950 -3.9970 3.2970 -4.0020 3.2950
which can be of any size, now i want to place all the values so that 3rd n 4 th coulm values comes under the end of 1st and 2nd row and so on all other tow pair columns values come under first n 2nd row
  3 件のコメント
Jan
Jan 2013 年 2 月 5 日
編集済み: Jan 2013 年 2 月 5 日
This cannot work for a [n x 6] matrix, because the result is not rectangular anymore. What do you want as output for:
x = [1,2,3,4,5,6] ?
Liaquat Ali
Liaquat Ali 2013 年 2 月 5 日
I have matrix like
f =
1 2 3 4 3 2 6 7
1 2 3 4 3 2 6 7
1 2 3 4 3 2 6 7
5 6 7 8 3 2 6 7
9 10 11 12 3 2 6 7
13 14 15 16 3 2 6 7
and i want the result to be f3 =
1 2
1 2
1 2
5 6
9 10
13 14
3 4
3 4
3 4
7 8
11 12
15 16
3 2
3 2
3 2
3 2
3 2
3 2
6 7
6 7
6 7
6 7
6 7
6 7
Thanks man i have already done it, I do not know whether i can post the answer my self or not ..............lols

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採用された回答

ChristianW
ChristianW 2013 年 2 月 5 日
reshape([M(:,1:2:end) M(:,2:2:end)],[],2) % M is your Matrix

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