Is there an algorithm to split a dataset of a few thousand points into multiple "chunks" of length 'n'?

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KSSV
KSSV 2020 年 10 月 15 日
編集済み: KSSV 2020 年 10 月 15 日

1 投票

Read about reshape.
A = rand(1,1000) ;
n = 100 ;
iwant = reshape(A,100,[]) ;
size(iwant)
iwant(:,1) % 10 columns of 100 rows

1 件のコメント

Xuan Gip
Xuan Gip 2023 年 6 月 27 日
is there any way to reshape based on a pattern? For example, I have a data that goes 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 and I want the reshape the entire data set to start from that first "1" to the last "1" on the second group of 1s.

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Ameer Hamza
Ameer Hamza 2020 年 10 月 15 日

1 投票

Another approach is to create a cell array.
M = rand(1, 1000);
n = 100;
C = mat2cell(M, 1, n*ones(numel(M)/n, 1))

3 件のコメント

j bar
j bar 2020 年 10 月 15 日
I get the following error:
This is probably due to 'M' not being an integer when divided by 'n'. What is the best way to fix this?
Error using ones
Size inputs must be integers.
Ameer Hamza
Ameer Hamza 2020 年 10 月 16 日
Your number of elements in vector M must be a multiple of 'n'. If it is something else, you will get that error.
KSSV
KSSV 2020 年 10 月 16 日
  1. Try to make M divisble by n, by appending NaN's to your array.
  2. Or make first few chunks of same size and leave last chunk with reduced elements

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