Closing specific figure handles

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Jared
Jared 2013 年 2 月 1 日
I asked a similar question before, but haven't been able to get the behavior I am looking for.
Example. I can have up to 4 plots p(1)=figure, p(2), p(3), p(4)... I can also have up to 4 histograms h(1)=figure, h(2), h(3), h(4)...
Using a for loop to determine the user desired output, figures are created, then the plot or histogram is "put in" each figure.
Due to the nature of how I am creating the figures, I am not sure which ones are open, so I can't just do:
close(p(1)); close(p(2)); close(p(3)); close(p(4));
Same for h(i). Is there a way to close all of p, or h, with a single command, no matter if one or all of them are open?

採用された回答

Matt Tearle
Matt Tearle 2013 年 2 月 1 日
編集済み: Matt Tearle 2013 年 2 月 1 日
Why not just do close(h)?
If there's a possibility that h never gets created at all (no histograms), you can use exist to check before doing the close
if exist('h','var')
close(h)
end
EDIT Rereading the question, perhaps the problem is that h(2) may exist as a variable, but not refer to a valid figure? In that case,
close(h(ishandle(h)))

その他の回答 (1 件)

Shashank Prasanna
Shashank Prasanna 2013 年 2 月 1 日
close(findobj('type','figure'))
Closes all figures.
  1 件のコメント
Jared
Jared 2013 年 2 月 1 日
I don't want to close all figures. I want to close all p figures, or all h figures, while leaving the others open. Can findobj be used to find the handle p or h?

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