ploting reversed laplace function

Why is it not working?, please help syms s; y =(4.36/(s*(s^2+1.61*s+0.935+4.36))); ilaplace(y) t = 0:0.001:8; plot(t,y, '-r' )

3 件のコメント

eliman
eliman 2011 年 4 月 23 日
syms s;
y =(4.36/(s*(s^2+1.61*s+0.935+4.36)));
ilaplace(y)
t = 0:0.001:8;
plot(t,y, '-r' )
Andrew Newell
Andrew Newell 2011 年 4 月 23 日
Thanks for formatting the code. It would be better, though, to edit your original question.
Andrew Newell
Andrew Newell 2011 年 4 月 23 日
In your question you should also say how it is not working. In this case, you are getting an error message:
??? Error using ==> plot
Conversion to double from sym is not possible.

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回答 (1 件)

Andrew Newell
Andrew Newell 2011 年 4 月 23 日

0 投票

The Symbolic Toolbox does not substitute numeric values of t into the expression unless you ask it to. You could do this:
plot(t,subs(y,t),'-r')

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