Solving non linear equation

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Shahzaib Gul
Shahzaib Gul 2020 年 10 月 2 日
回答済み: Alan Stevens 2020 年 10 月 2 日
I want to calculate the value of x1 from that equation..So this is one equation and one unknown in it..As it contains theeta so therefore it is a non linear equation..So i have used fsolve for that and it has also calculated the result but the thing is result is not correct....the value of x1 should be 0.16 or closer than that..But i have got 0.0315 so i dont know which mistake i am making...Can anyone help please?
  3 件のコメント
Shahzaib Gul
Shahzaib Gul 2020 年 10 月 2 日
function F=myfun(x)
F=[(0.23544*cos(0))+(0.23544*cos(180))+(0.23544*cos(180))+(1.4715*x(1)*cos(0))];
end
Shahzaib Gul
Shahzaib Gul 2020 年 10 月 2 日
Yes sir this is the required code...Please looking for help

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回答 (1 件)

Alan Stevens
Alan Stevens 2020 年 10 月 2 日
Use cosd instead of cos. cosd assumes the argument is in degrees, cos assumes the argument is in radians.

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