Decimal random number generator

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sita
sita 2013 年 1 月 25 日
編集済み: Thorsten 2015 年 10 月 26 日
Hello,
I want to generate a random number generator 0 to 1 should include values with ten decimal points.As default i get only 4 decimals.
Thanking You,
Sita
  1 件のコメント
Jan
Jan 2013 年 1 月 28 日
Where did all the comments go? Did you delete them? If so, why? Without them our answers looks a little bit unmotivated, not to say lunatic. Therefore removing important data from a thread is not wanted.

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回答 (3 件)

Sachin Ganjare
Sachin Ganjare 2013 年 1 月 25 日
編集済み: Jan 2013 年 1 月 25 日
out = rand(1, 1);
decimal_out = floor(out * 100000000);
decimal_out = decimal_out\100000000;
  2 件のコメント
Cy
Cy 2015 年 10 月 26 日
Don't you mean "decimal_out/100000000"?
Thorsten
Thorsten 2015 年 10 月 26 日
編集済み: Thorsten 2015 年 10 月 26 日
Your're right, that's a typo, must read /. Of course you can do it more efficiently in one line (for example, to generate a row vector of four random values):
x = floor(rand(1,4)*1e10)/1e10;

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Jan
Jan 2013 年 1 月 25 日
What about using rand() directly, because it satisfies: at least 8 decimal digits already?
  1 件のコメント
Jan
Jan 2013 年 1 月 25 日
編集済み: Jan 2013 年 1 月 25 日
The limitation to 4 digits appears in the command line only, see: help format.
format long g
disp(rand(2,2))
Although I assume your code is just an abbreviated example, I recommend not to use "min" and "max" as names of variables, because this shadows frequently used Matlab commands.
However, I still do not understand your question. What does "fixing the number of decimal points" mean? RAND does reply values like 0.00000000001 also, so what is the problem.

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Evgeny Pr
Evgeny Pr 2013 年 1 月 25 日
編集済み: Evgeny Pr 2013 年 1 月 25 日
Do you have the distribution law for pseudo-random numbers for your problem? You can use RAND function for generate uniformly distributed numbers and define its non-linear (or linear) transformation function:
numbers = rand(10);
transformedNumbers = transform_function(numbers);

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