fsk modulator and demodulator
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i have this code and although i added noise to it the bit error rate is still zero.. any clue?!!
%%%%%%%%%%%%%fsk mod and demod%%%%%%%%%%%%%%%%%%%%
M = 2;
k = log2(M);
EbNo = 5;
Fs = 16;
nsamp = 17;
freqsep = 8;
n=100;
msg = randint(n,1,M); % Random signal
txsig = fskmod(msg,M,freqsep,nsamp,Fs); % Modulate.
ab=abs(txsig);
ps=(sum(ab.^2))/n;
snr=30;
pn=10.^(-0.1.*snr).*ps;
noise= sqrt(pn)*randn(1,n);
G1=randn(1,n); %generation of Gaussian noise
G2=randn(1,n);
v= sqrt(power(G1,2)+ power(G2,2));
A=v(2);
theta=2*pi*rand;
msg_rx = A*exp(j*theta)*txsig + noise(3); %flat fading
msg_rrx = fskdemod(msg_rx,M,freqsep,nsamp,Fs); % Demodulate
[num,BER] = biterr(msg,msg_rrx) % Bit error rate
BER_theory = berawgn(EbNo,'fsk',M,'noncoherent') % Theoretical BER
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その他の回答 (1 件)
Walter Roberson
2011 年 4 月 21 日
You calculate v=sqrt(G1.^2+G2.^2) where G1 and G2 are 1 x n. You then take v(2) and throw away the rest of v. What is the point of doing all of that, when you could just do
A = sqrt(randn^2+randn^2);
This hints that you are doing something wrong. As does the fact that you use only noise(3) when noise is 1 x n .
You need to check out the magnitude of noise(3) and compare it to the magnitude of A*exp(j*theta)*txsig -- if noise(3) is very small then it would be as if you had not added the noise, merely phase-shifted the signal.
4 件のコメント
Salma
2011 年 4 月 21 日
Walter Roberson
2011 年 4 月 21 日
It doesn't matter what noise(17) is, as you only use noise(3)
Salma
2011 年 4 月 21 日
Salma
2011 年 4 月 29 日
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