How do I plot individual circles whose centers are points on a graph?
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I generated some random numbers which represent random forces acting on a spring, I then divided this random forces by a spring constant 20.5 to get the random positions (using Hooke's Law), I selected the random positions between -50 and 50. This random positions were then plotted (using the code below);
x_max=50.0;
x_min=-50.0;
N = 100;
RandFor = 1030*rand(N,1) .* sign(randn(N,1));
k= 20.5;
x=RandFor./k;
x(x_min > x | x > x_max) = 0;
scatter( 1:length(x), x, 75,[0 0 0],'filled' )
plot(x)
figure(1)
%subplot(1,3,1:2)
xlabel('frames');
ylabel('Random Positions');
I need to plot individual circles centered on each plotted random position, thus for above code there should be 100 circles. These circles are one dimensional because the random positions are plotted only on the y-axis. so the circles have only y co-ordinates, the x-axis represents the captured frame of each circle.
I tried using the code below to plot the circle
function circle(a,b,r)
%x and y are the coordinates of the center of the circle
%r is the radius of the circle
%0.01 is the angle step,
ang=0:0.01:2*pi;
xp=r*cos(ang);
yp=r*sin(ang);
plot(a+xp,b+yp);
hold on;
end
But I don't know how to make the circle appear on each random position.
0 件のコメント
採用された回答
Walter Roberson
2013 年 1 月 18 日
You can use scatter() to plot circles. The third parameter to scatter() is the size of the circle.
9 件のコメント
Walter Roberson
2013 年 1 月 24 日
Consider circle #17 (for example.) In frame #2, should only the new position of circle #17 be shown, or should both the old and new positions be shown?
If you want the positions to accumulate on the same graph, then just ensure you have done
hold on
after doing the first scatter().
その他の回答 (1 件)
disha
2013 年 4 月 5 日
You can try the following modification in your code. plot(x,y,'--rs','LineWidth',2,... 'MarkerEdgeColor','k',... 'MarkerFaceColor','g',... 'MarkerSize',10) Hope this helps.
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