Error with delta function Matlab 2019

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S Foggie
S Foggie 2020 年 9 月 4 日
コメント済み: Star Strider 2020 年 9 月 4 日
Hello, I have been trying to get the delta function to work with my version of Matlab 2019. I have tried various combinations of code but I keep getting the errors when I try to use delta, even when I declare it as a variable.
Here's an example that I think should work but I keep getting this error. Can someone point me in the right direction of what I am missing?
error:
Insufficient number of outputs from right hand side of equal sign to satisfy assignment.
Here's the code I'm trying to run..
close all;
clc
N = 60; n = 0:N-1;
b = [0.18 0.1 0.3 0.1 0.18];
a = [1 -1.15 1.5 -0.7 0.25];
[d nd] = delta(n(1),0,n(end));
[u nu] = unitstep(n(1),0,n(end));
y1 = filter(b,a,d);
y2 = filter(b,a,u);
Thanks

採用された回答

Star Strider
Star Strider 2020 年 9 月 4 日
I have no idea what you actually want to do.
It is generally appropriate to use filtfilt rather than filter for signal processing applications, and to put the excitation signal in the centre of the vector, especaially if you want to do Fourier transforms on it later. Also, I can find no reference for either ‘delta’ or ‘unitstep’. I have substituted the functions that I can find references for.
Try this:
N = 60; n = 0:N-1;
b = [0.18 0.1 0.3 0.1 0.18];
a = [1 -1.15 1.5 -0.7 0.25];
d = dirac(1);
u = heaviside(1);
nd = n;
nu = n;
nd(N/2) = d;
nu(N/2) = u;
y1 = filter(b,a,nd);
y2 = filter(b,a,nu);
figure
plot(n, y1, n, y2)
grid
Experiment to get the results you want.
  4 件のコメント
S Foggie
S Foggie 2020 年 9 月 4 日
Thank you again! This information was very helpful
Star Strider
Star Strider 2020 年 9 月 4 日
My pleasure!
If my Answer helped you solve your problem, please Accept it!
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