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find expression within {}

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Ajay krishna Vasanthakumar
Ajay krishna Vasanthakumar 2020 年 8 月 20 日
Hello all,
i have to fin {i++;} from the below expression using regexp.can some one help me out?
x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};
i tired using the below regexp
regexp(x,'[^/]\s*{.*}','match')
output : ']{i++;}/{a =1;}'
Thanks,
Ajay
  2 件のコメント
Rik
Rik 2020 年 8 月 20 日
Although you can do it with regexp, why would you? strfind will do the job here. What do you want to do with the result?
Ajay krishna Vasanthakumar
Ajay krishna Vasanthakumar 2020 年 8 月 20 日
i just want to to pick the chars inside {.*}.i dont want to pick /{.*} and append some varibales using regexprep.

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Rik
Rik 2020 年 8 月 20 日
You were close: you forgot to make the expression lazy, and you forgot you included the close bracket from the sting when excluding the / matched part.
str='x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};';
a=regexp(str,'[^/]({.*?})','tokens');
a{1}
  1 件のコメント
Ajay krishna Vasanthakumar
Ajay krishna Vasanthakumar 2020 年 8 月 20 日
編集済み: Ajay krishna Vasanthakumar 2020 年 8 月 20 日
Thanks alot rik :)
i did a small correction to the expression
str='x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};';
a=regexp(str,'(?<!/\s*){.*?}','match');
a{1}
just to make sure the before letter is not followed by /.

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