passing 'varagin' and getting inputname() to work properly

Is it possible to pass 'varargin' to an internal function and still get inputname() to return the original variable names?

e.g.

function struct = temp( varargin )
    struct = parseInputs( varargin{1:end} )
end

function struct = parseInputs( varargin )
    struct.name1 = inputname(1);
    struct.name2 = inputname(2);
    struct.name3 = inputname(3);
    struct.name4 = inputname(4);
end

>> output = temp( a, b, c, d )

output =

    name1: 'a'
    name2: 'b'
    name3: 'c'
    name4: 'd'

Answer 1

[Jonathan Sullivan]

You could use "evalin"

In your example it would be something like:

function struct = temp( varargin )
    struct = parseInputs( varargin{1:end} )
end

function struct = parseInputs( varargin )
    for ii = 1:length(varargin)
        struct.(['name' num2str(ii)]) = evalin('caller',['inputname(' num2str(ii) ');']);
    end

end