How to integrate a matrix of a certain dimension?!

2 ビュー (過去 30 日間)
Shashank
Shashank 2012 年 12 月 19 日
Suppose I have a temperature matrix, T = zeros(Nz+1,Nt+1). Nz are number of elements in the z-axis and Nt are number of elements in the time-axis.
What command should I use for calculating the following integral?
E = integral of [A*T(z,:)*exp(-B*z)] with limits z = 0 to L.
Here, the temperature inside the integral is a function of the position z at a certain time.
Any kind of help will be appreciated. Thanks.
  6 件のコメント
Shashank
Shashank 2012 年 12 月 19 日
Walter, could you help with the syntax for trapz() in my case?!
Nt = 100; Nz = 100;
dz = 1/100;
z = 0:dz:Lz;
TSi = zeros(Nz+1,Nt+1);
Y(i) = (TSi(1:end,i).^4)*exp(-A*z);
% A is a constant, "i" is the ith timestep
T_integral(i) = trapz(z,Y(i));
I am having trouble with dimension mismatch. Could you please tell me how to define Y such that it integrates over ith column of TSi only?!
Shashank
Shashank 2012 年 12 月 19 日
Or is there a way to convert the temperature data points into a polynomial so that calculation becomes easy? Maybe use a curve-fit?

サインインしてコメントする。

回答 (1 件)

Muruganandham Subramanian
Muruganandham Subramanian 2012 年 12 月 19 日
編集済み: Muruganandham Subramanian 2012 年 12 月 19 日
  1 件のコメント
Shashank
Shashank 2012 年 12 月 19 日
Thanks for your answer. But that does not help somehow.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeNumerical Integration and Differentiation についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by