Bit xor of row with the next row and the output is again xored with the next row

Hi, I have a image and I want to xor first row with single number then Xor 2nd row with first, the output is xored aith the next row and so on. I hope some one can figure out the mistake

for example

c=245;
A=[23 2 13;34 56 70;12 18 90];
a=[];
[m n]=size(A);
for i=2:m
a1=bitxor(c,A(1,:));   %Xor c with each element of first row of A 
(a(i),:)=bitxor(a(i-1),A(i,:));% error ,Index exceeds matrix dimension

end

Answer 1

[Walter Roberson]

c = 245;
A = [23 2 13;34 56 70;12 18 90];
a = [];
[m, n] = size(A);
a(1,:) = bitxor(c,A(1,:));   %Xor c with each element of first row of A 
for i = 2:m
  a(i,:) = bitxor(a(i-1),A(i,:));
end

[lilly lord]

I am checking it with simple values like

c=11;
A=[3 2 13;4 5 7;12 8 9];
a=[];
[m n]=size(A);
a(1,:)=bitxor(c,A(1,:));
for i=2:m
a(i,:)=bitxor(a(i-1),A(i,:));
end
a;
The output is 
8	9	6
12	13	15
0	4	5
which is a wrong
Correct output should be
8	9	6
12	12	1
0	4	8

Can u please figure out where is the problem

[Walter Roberson]

for i=2:m
  a(i,:)=bitxor(a(i-1, :),A(i,:));
end

[lilly lord]

Thanks. You solved my problem