how to generate a polynomial
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i have two matrix one is
s=[2 3
4 5]
other is
text = [3 5 6 7
3 4 5 6]
based on my threshold value i should form a polynomial
say for exam threshold is 2 my polynomial should be
P= s(1,1)*x^0 + text(1,1)*x^1
if threshold is 3 my polynomial should be
P= s(1,1)*x^0 + text(1,1)*x^1 + text(1,2)*x^2 i have to process for every
digit like this .... value from should be taken once but from text van be any
number of times based on threshold...
Thanks in advance ..i am not able to trace it out please help
15 件のコメント
Azzi Abdelmalek
2012 年 11 月 24 日
編集済み: Azzi Abdelmalek
2012 年 11 月 24 日
Then why t(2,1) is repeated?
Walter Roberson
2012 年 11 月 24 日
In Sharen's comment http://www.mathworks.co.uk/matlabcentral/answers/54693-how-to-generate-a-polynomial#comment_113211, t(2,1) appears only once.
採用された回答
Azzi Abdelmalek
2012 年 11 月 24 日
編集済み: Azzi Abdelmalek
2012 年 11 月 24 日
s=[2 3 ;4 5]
text = [2 3 4; 5 6 7; 4 5 6]
t=text.'
t=t(:)
th=3;
x=11
[n,m]=size(s)
c=1:th-1;
idx1=1;
idx2=th-1;
for k=1:n
for l=1:m
t1=t(idx1:idx2).'
P(k,l)=s(k,l)+sum(t1.*x.^c)
idx1=idx1+th-1
idx2=idx2+th-1
end
end
3 件のコメント
その他の回答 (2 件)
Azzi Abdelmalek
2012 年 11 月 24 日
編集済み: Azzi Abdelmalek
2012 年 11 月 24 日
s=[2 3 ;4 5]
text = [3 5 6 7 3 4 5 6]
threshold=4;
x=11
c=1:threshold-1
P=s(1,1)+sum(text(c).*x.^c)
2 件のコメント
Matt Fig
2012 年 11 月 24 日
Sharen, please fill in the blank and define the ranges:
P(m,n) = _________________________
(for m = 1:size(s,1) and n = 1:size(s,2)) <---- correct??
0 件のコメント
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