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sortrows graph edges .

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Rub Ron
Rub Ron 2020 年 6 月 6 日
コメント済み: Christine Tobler 2021 年 1 月 8 日
I have a graphs G. The G.Edges has 300 elements. I would like to sort the edges of my graph based on a given index (of size 300x1). I tried:
G.Edges = sortrows(G.Edges,index);
but it gives me an error:
Error using tabular/sortrows (line 57)
Variable index exceeds table dimensions.
I also tried to sort it based in the weight of the edges, but it does not work either.
G.Edges = sortrows(G.Edges,'Weight','ascend');
Any help will be appreciatted.
  2 件のコメント
darova
darova 2020 年 6 月 15 日
what does it mean?
Rub Ron
Rub Ron 2020 年 6 月 15 日
@darova index is the new position sof the edges. Considering the inital position (as listed) of the edges were: [1 2 3 4 ... 300]

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回答 (2 件)

Christine Tobler
Christine Tobler 2020 年 6 月 15 日
編集済み: Christine Tobler 2020 年 6 月 15 日
The variable G.Edges.EndNodes of a graph can't be modified, it is always sorted by the nodes in the graph. This is so that the presentation is standardized, meaning that two graphs that have the same nodes and edges will present as the same.
You can save the sorted edges table into another variable, though:
weightSortedEdges = sortrows(g.Edges, 'Weight')
if this index is captured as the weight of each edge, or based on the index variable:
[~, ind] = sort(index);
indexSortedEdges = g.Edges(ind, :);
  7 件のコメント
KIN WONG
KIN WONG 2021 年 1 月 7 日
@Steven Lord
I encountered the same issue. Based on a little bit of testing, it appears to me that the graph constructor uses command "sortrows" to preprocess the Edges table.
Since this is a crucial aspect needed to maintain correspondence between edge index and additional edge-associated data, could this fact be (1) made official and permanent, and (2) documented on the MATLAB help page?
Namely:
Please consider accepting this documentation change request. Thank you.
Christine Tobler
Christine Tobler 2021 年 1 月 8 日
I've passed this information along, thank you for the detailed comments. A note on "Compatibility Considerations" - we only use these when a behavior has changed, which isn't the case here since the Edges table has always been sorted and will stay so in the future.

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Walter Roberson
Walter Roberson 2020 年 6 月 15 日
The second parameter to sortrows() being applied to a table, must be either 'rownames' or indications of the variables to sort on. A numeric vector can be given, in which case the entries represent variable numbers -- which would be 1 to the width of the Edges table, not to the height of the Edges table.
If you want the edges table to be in a particular order, then
G.Edges = G.Edges(index,:);
  1 件のコメント
Rub Ron
Rub Ron 2020 年 7 月 19 日
Hi, unfortunately in my case G is not a table, it is a graph. So, this does not work for me.

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