For Loop to generate value alternately

Good morning,

I would like to ask you some help with writing a script. I have a beam with variable length. On this beam there are two types of load, whose values are 4 and 8. These two values alternate every 3 meters. I would like to write a script that for a number of times, starting from a fixed length, adding three meters for every loop, automatically it alternates the value of 4 and of 8.

For example starting from a beam of 12 meters, I have the loads which are 4, 8, 4 equidistant (3 meters from each other). I want to start a loop of 10 iteration, which adds 3 meter to the starting beam length (12 + 3) and add the load equal to 8 for the first iteration; for the second iteration it adds again 3 meters (12 + 3 + 3) and the added load is 4. These procedure should be performed n times.

Thanks a lot for your availability.

Answer 1

[Paresh yeole]

% initialize n 
length_of_beam = 12;
for i = 1 : n      
    length_of_beam = length_of_beam +3;
    if mod(i,2) == 0
        load(i) = 8;
    else
        load(i) = 4;
    end
end

[Tommaso Donolato]

I need as output the length of each iteration (so a vector 1 x n , where n are the n iteration and a matrix, where the rows correspond to the n iteration and the columns are the sum of the values of the loads ( first iteration = 4 8 4 (16), second iteration = 4 8 4 8 (24) and so on). In the end I have 2 vector 1 x n

[Paresh yeole]

Looks like it is a homework assignment. Sorry I can't help you with that.

[Tommaso Donolato]

It's for my thesis. The last part of it needs this script.

[Paresh yeole]

% initialize n 
length_of_beam(1) = 12;
load(1) = 4;
for i = 2 : n       
    length_of_beam(i) = length_of_beam(i-1) +3;
    if mod(i,2) == 0
        load(i) = load(i-1) + 8;
    else
        load(i) = load(i-1) + 4;
    end
end
% you have two 1 * n vectors length_of_beam and load

[Tommaso Donolato]

Thank you very much, it works perfectly.