Matlab error "Matrix dimensions must agree"

I'm trying to get the integral() of a two functions but I keep getting this error and I don't know why
This is the code for the functions:
R = 0.5; %m
I = 2; %A
u0 = 4*pi*10^-7;
BiotSavart = (u0*R*I)/(4*pi);
max = 50;
px = -R:R/max:R;
py = -R:R/max:R;
pz = 0:R/max:2*R;
fy = @(t) sin(t)./((px-R*cos(t)).^2+(py-R*sin(t)).^2+pz.^2).^(3/2);
fz = @(t) (R-py.*sin(t)-px.*cos(t))./((px-R*cos(t)).^2+(py-R*sin(t)).^2+pz.^2).^(3/2);
By = pz * BiotSavart * integral(fy,0,2*pi);
Bz = BiotSavart * integral(fz,0,2*pi);
I get the error in this line:
fy = @(t) sin(t)./((px-R*cos(t)).^2+(py-R*sin(t)).^2+pz.^2).^(3/2);

 採用された回答

Star Strider
Star Strider 2020 年 5 月 28 日

0 投票

Integrating an array, set 'ArrayValued' to 'true':
By = pz .* BiotSavart .* integral(fy,0,2*pi, 'ArrayValued',1);
Bz = BiotSavart * integral(fz,0,2*pi, 'ArrayValued',1);
That runs without error.

2 件のコメント

Andrés Olvera
Andrés Olvera 2020 年 5 月 28 日
That worked, thanks! :D
Star Strider
Star Strider 2020 年 5 月 28 日
As always, my pleasure!

サインインしてコメントする。

その他の回答 (1 件)

Clemens Dierks
Clemens Dierks 2020 年 11 月 5 日

0 投票

Hello everybody,
I have the same error in a different situation.
I wrote the function to save two variables (matrices) in a xlsx file within two sheets.
Because xlswrite seems to be deprecated I used 'writematrix'.
A is 9000x2 matrix.
B is 1x1 vector.
The error occurs in when calling the method "writematrix".
Thank you in advance! :)
This is my code:
function [] = save_data(filename, A, B)
save(filename,'solution','DBC10');
writematrix(A, strcat(filename+'.xlsx'), 'sheet', 1)
writecell(B, strcat(filename+'.xlsx'),'sheet', 2)
end

カテゴリ

ヘルプ センター および File ExchangeLinear Algebra についてさらに検索

製品

リリース

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by