Hello, I am trying to use a for loop to solve an ODE by way of Euler's method. I have a loop that works for a single step size h = 0.05, but I was wondering if I can get the loop to run with h = [0.05 0.1 0.2], and then plot the three different outputs? Here is the code that I have so far, loops confuse me so any help is greatly appreciated.
y0 = 0;
t0 = 0;
tf = 1;
h = 0.05;
f = @(t,y) y^2 + 1;
y = y0;
y_1 = y;
for t = t0:h:tf-h
yp = f(t,y);
y = y + h*yp;
y_1 = [y_1 ; y];
end
x = 0:h:1;
plot(x,y_1)

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Ameer Hamza
Ameer Hamza 2020 年 5 月 26 日
編集済み: Ameer Hamza 2020 年 5 月 26 日

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H = [0.05 0.1 0.2];
figure;
hold on
for i=1:numel(H)
y0 = 0;
t0 = 0;
tf = 1;
h = H(i);
f = @(t,y) y^2 + 1;
y = y0;
y_1 = y;
for t = t0:h:tf-h
yp = f(t,y);
y = y + h*yp;
y_1 = [y_1 ; y];
end
x = 0:h:1;
plot(x,y_1, 'DisplayName', ['H = ' num2str(H(i))])
end
legend

1 件のコメント

Travis Girton
Travis Girton 2020 年 5 月 26 日
Thank you, I was trying something simular to this but with both loops later in the code and couldn't get it to work. Starting the loop much earlier makes sense now that I see it.

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