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NN
NN 2012 年 11 月 8 日

2 投票

Might help
Imagearray=double(imread('image's name (path).Image type e.g. tiff'));

2 件のコメント

Elysi Cochin
Elysi Cochin 2012 年 11 月 8 日
Thanks all
Image Analyst
Image Analyst 2012 年 11 月 8 日
Or maybe when you say write you mean imwrite to write the image array out to disk:
imwrite(yourImage, filename);
Using precise unambiguous terminology is important if you want a precise answer.

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その他の回答 (3 件)

Harshit
Harshit 2012 年 11 月 8 日

0 投票

Why do you wanna write an image into an array. Use reshape if you really want.
Walter Roberson
Walter Roberson 2012 年 11 月 8 日

0 投票

get() the CData property of the image; that will be an array.
Mohammed Manna
Mohammed Manna 2012 年 11 月 8 日
編集済み: Mohammed Manna 2012 年 11 月 8 日

0 投票

Simply do this
targetImg = imread("path");
targetImg = targetImg(:); % You can take a transpose too if you like
If you need to convert it to one of the primitive types, you can do so by
targetImg = double(targetImg);
targetImg = float(targetImg);
% etc.
If you have performance/speed/parallel processing related issues. I suggest you also look into get() CDATA property of the image. I am not sure why you need the array of an image. I must say that I cannot remember if about the float(). But the point is proven. Hope this helps you.

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