find coordinates within a matrix
10 ビュー (過去 30 日間)
古いコメントを表示
Suppose I have the following matrices:
b= 0.85981
0.87169
and
a=
0.855750000000000 0.858420000000000 0.858110000000000 0.858210000000000 0.858880000000000
0.857680000000000 0.858700000000000 0.858920000000000 0.858480000000000 0.858630000000000
The first value of "b" (0.8591) is contained in the first row of variable "a" whilst the second value of "b" (0.87169) is found in the second row of variable "a".
My question is how can I find which column number or position "b" has in "a"?
0 件のコメント
回答 (1 件)
Ameer Hamza
2020 年 5 月 3 日
編集済み: Ameer Hamza
2020 年 5 月 3 日
the elements of 'b' given in the question are not actually present in the matrix 'a', so I used values in b from 'a'
a = [
0.855750000000000 0.858420000000000 0.858110000000000 0.858210000000000 0.858880000000000
0.857680000000000 0.858700000000000 0.858920000000000 0.858480000000000 0.858630000000000];
b = [0.85811
0.8587];
[~,c] = find(a==b);
Result:
c =
2
3
Note that, if the values are not exactly the same, then you will need to do the comparison with a tolerance value like this
[~,c] = find(abs(a-b)<1e-6); % 1e-6 is tolerance value
2 件のコメント
Ameer Hamza
2020 年 5 月 3 日
Tolerance value in ismembertol is always a bit non-intuitive. I always find it easier to write it using abs().
参考
カテゴリ
Help Center および File Exchange で Matrix Indexing についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!