10 minutes average for four hours data
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3793.197 3793.19735 3793.1977 3793.19805 3793.1984 3793.19875 3793.1991 3793.19945 3793.1998 3793.20015 3793.2005 3793.20085 3793.2012 3793.20155 3793.2019 3793.20225 3793.2026 3793.20295 3793.2033 3793.20365 3793.204 3793.20435........etc i have a data set for four hours....these datas are taken in 15 seconds interval and for four hours i will have 720 datas .....for the first hour i need to calculate average for first 10 minutes and remaining 50 minutes no need to calculate average and again for second hour, first 10 minutes i need to calculate average and so on til the completion of four hours.......since i m a beginner in matlab .....i need a help sir to write a matlab code for 10 minutes average for four hours data....
3 件のコメント
Azzi Abdelmalek
2012 年 10 月 29 日
why 720, in 4 hours you will have 4 * 60 *4 =960
Walter Roberson
2012 年 10 月 29 日
Please do not name individuals in your Tags. Please retag this question; see http://www.mathworks.co.uk/matlabcentral/answers/43073-a-guide-to-tags
PRIYA
2012 年 10 月 30 日
採用された回答
その他の回答 (2 件)
Sachin Ganjare
2012 年 10 月 29 日
0 投票
A=rand(960,1);
A=reshape(A,240,4);
A_OUT=mean(A(1:40,:))
Sachin Ganjare
2012 年 10 月 30 日
0 投票
A=rand(720,1);
A=reshape(A,240,3);
A_OUT=mean(A(1:40,:))
3 件のコメント
Sachin Ganjare
2012 年 10 月 30 日
For your 3hrs requirment, above code will suffice.
PRIYA
2012 年 10 月 30 日
Andrei Bobrov
2012 年 10 月 30 日
A=rand(720,1);
A=reshape(A,240,[]);
A_OUT=mean(A(1:40,:));
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