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Group Constraints for FMINCON

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Tommaso Belluzzo
Tommaso Belluzzo 2020 年 4 月 26 日
編集済み: Tommaso Belluzzo 2020 年 4 月 26 日
Hi all! I'm writing a model that needs to minimize 6 variables through FMINCON: o, a, b, w, kappa, gamma. The variable options is defined as follows:
The variables are already subject to the following lower/upper boundaries:
  • o, a, b, w between 0 and Inf;
  • kappa, gamma strictly positive between (2 * options.TolCon) and Inf;
I need to ensure a few constraints are respected:
  • o, a, b, w must approximately sum to 1;
  • kappa * gamma must be approximately equal to 1;
If I didn't have to consider the last two variables, I would have probably used A and b parameters of FMINCON as follows:
A = [-eye(3); ones(1,3)];
b = [(zeros(3,1) + (2 * options.TolCon)); (1 - (2 * options.TolCon))];
But going for that approach with two distinct constraints (an additive one and a multiplicative one) is pretty weird and I really have no clue about how to set A and b.
It seems that the nonlcon parameter may be what I'm looking for, but it's unclear to me how to formulate it properly.

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John D'Errico
John D'Errico 2020 年 4 月 26 日
Approximately equals is NOT an equality constraint.
But you can write it as TWO inequality constraints. So if you want kappa*gamm approximately equal to 1, then that means you want the product to be within some given tolerance of 1. That is:
kappa*gamm >= 1 - tol
kappa*gamm <= 1 + tol
You can then swap the inequality direction on the first constraint by multiplying by -1.
-kappa*gamm <= -(1 - tol)
Note my use of gamm as a variable name, instead of gamma. Since there is a function called gamma that is often quite useful, I strongly suggest not using a variable named gamma.

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Tommaso Belluzzo
Tommaso Belluzzo 2020 年 4 月 26 日
Thanks for your answer. May I kindly as you how I can implement this on the point of view of Matlab code?
I think I have to write a nonlcon function like this?
function [c,ceq] = my_nonlcon(x,options)
kappa = x(5);
gamm = x(6);
kg = kappa * gamm;
c1 = kg - (1 - (2 * options.TolCon));
c2 = kg - (1 + (2 * options.TolCon));
c = [c1; c2];
ceq = [];
Together with A and b contraints formulated as follows:
A = [[-eye(3) zeros(3)]; [ones(1,4) zeros(1,2)]; zeros(2,6)];
b = [(zeros(3,1) + (2 * options.TolCon)); (1 - (2 * options.TolCon)); zeros(2,1)];
Am I right?


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