Unable to convert expression into double array.

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Andrea Gusmara
Andrea Gusmara 2020 年 4 月 25 日
コメント済み: Andrea Gusmara 2020 年 4 月 25 日
syms fi ;
syms theta;
syms psi;
rM=[cos(fi)*cos(theta)*cos(psi)-sin(fi)*sin(psi) -cos(fi)*cos(theta)*sin(psi)-sin(fi)*cos(psi) cos(fi)*sin(theta) ;
sin(fi)*cos(theta)*cos(psi)+cos(fi)*sin(psi) -sin(fi)*cos(theta)*sin(psi)+cos(fi)*cos(psi) sin(fi)*sin(theta);
-sin(theta)*cos(psi) sin(theta)*cos(psi) cos(theta)];
transition=[x y z]';
zeros=sym(zeros(1,3));
one=sym(ones(1));
hM=[rM transition ;
zeros one];
hM=double(hM);

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Radu Trimbitas
Radu Trimbitas 2020 年 4 月 25 日
It is not clear what do you want. Your expressions are entirely symbolic. If you want to give later values to x,y,z, phi, etc try to convert hM to a MATLAB function with matlabFunction, eg
hMf=matlabFunction(hM);
and when you supply values for your symbolic variables you will obtain a double array
  1 件のコメント
Andrea Gusmara
Andrea Gusmara 2020 年 4 月 25 日
Yes I want to obtain a double expression from my symbolic hM. I have just tried to apply your advice and my program works correctly . I want to ask you another question , is it the only possible solution for update my simbolic expressions?. thanks for your help .

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