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Generating random numbers from Alpha-stable pdf which expends in time (in a loop)

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Erez
Erez 2020 年 4 月 13 日
コメント済み: Jeff Miller 2020 年 4 月 16 日
I asked first on another site, decided to ask here because I go no answers.
The following line of Matlab code generates 100000 random numbers from an Alpha-stable pdf (here Alpha=0.5):
Rand = random('Stable',0.5,0,1,0,[1,100000]);
The distribution of Rand exactly matches the the 'theoretical' curve generated by
PDF = makedist('Stable','alpha',0.5,'beta',0,'gam',1,'delta',0);
x = -5:.1:5;
PDF = pdf(PDF,x);
figure
plot(x,PDF,'r-.');
(to check, use, e.g.:)
Data=Rand;
Middle=0.01;
PosBinsUP=10.^(log10(Middle):0.05:log10(max(abs(Data))));
PosBinsDown=10.^(log10(Middle):0.05:log10(abs(min(Data))));
xbins=[-flip(PosBinsDown) -Middle:0.2:Middle PosBinsUP];
[xpdf ypdf]= plotpdfc(Data, xbins);
plot(xpdf(1:end-1),ypdf(1:end-1),'Or');
xlim([-5,5]);
My question is:
How do I generate these Rands in a loop over 't', such that their distribution will expand in time, namely P(Rand) = t^(-1/Alpha) W(Rand/ t^(1/Alpha))?
  4 件のコメント
Erez
Erez 2020 年 4 月 15 日
@ Jeff Miller I still don't see how ths could would make my PDF change with time. I want that different iterations of the loop over t will yields a broader PDF, corresponding to the sum of IID random numbers of where the number of summands is growing, and the Levy-generalized central limit theorem.
Of course, I could actually just sum random numbers, to get the PDF. But I am looking for a more direct way to obtain them, using the Matlab function above.
Thanks!
Jeff Miller
Jeff Miller 2020 年 4 月 16 日
Sorry, I don't really understand this distribution, so I don't have anything useful to contribute. It just seems that if you want a random number from the stable distribution at each t, then your only option is to adjust the stable's parameter values to be whatever you want for each t.

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