Perform AND operations with multiple matrices

2 ビュー (過去 30 日間)
KostasK
KostasK 2020 年 4 月 9 日
コメント済み: KostasK 2020 年 4 月 9 日
Hi all,
I am performing AND operations with multiple matrices, where I have a cell array M={1x3} containing three matrices of arbitrary dimensions, and a vector c=[1x3] containing three numbers. And with those I have to perform the below operation:
M = {rand(15), rand(15), rand(15)} ;
c = rand(1, 3) ;
i = find(M{1} == c(1) & M{2} == c(2) & M{3} == c(3)) ;
Since the second dimension of M and c are set to vary to any number (i.e. it could be 4,5,6, etc.), I was wondering wether there was a way to perform the AND (&) operation in a way which could account for the above, instead of manually ammending the code every time.
Thanks for your response in advance,
KMT.

採用された回答

Walter Roberson
Walter Roberson 2020 年 4 月 9 日
編集済み: Walter Roberson 2020 年 4 月 9 日
M = {rand(15), rand(15), rand(15)} ;
c = rand(1, 3) ;
cc = num2cell(c);
fold(@and, cellfun(@(V,C) V == C, M, cc, 'uniform', 0))
  1 件のコメント
KostasK
KostasK 2020 年 4 月 9 日
This one works well!

サインインしてコメントする。

その他の回答 (2 件)

Andrei Bobrov
Andrei Bobrov 2020 年 4 月 9 日
i = find(all(cat(3,M{:}) == reshape(c,1,1,[]),3));

Alexandra McClernon Ownbey
Alexandra McClernon Ownbey 2020 年 4 月 9 日
編集済み: Alexandra McClernon Ownbey 2020 年 4 月 9 日
This may not be the most efficient way, but it works. I stored everything in a logical and then compared the k-dimension in that logical. I also modified to randi with a range just so I can test it
M = {randi([-1,1],15,15), randi([-1,1],15,15), randi([-1,1],15,15)} ;
c = randi(1, 3) ;
ix = false(length(M{1}(1,:)),length(M{1}(:,1)),length(c));
for j = 1:length(c)
ix(:,:,j) = M{j} == c(j);
end
[l,m,n] = size(ix);
k = 1;
for i = 1:l
for j = 1:m
if all(ix(i,j,:))
row(k) = i;
col(k) = j;
k = k+1;
end
end
end
the locations of where c = M are located in row and col.

カテゴリ

Help Center および File ExchangeMatrices and Arrays についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by