random close numbers within an array
2 ビュー (過去 30 日間)
古いコメントを表示
how can i randomly extract a number and one of its four closest 'neighbours' out of an array 100x100?
5 件のコメント
Image Analyst
2020 年 4 月 5 日
How about if you make it easy and just pick a random row or column between 2 and 99.
x = 1 + randi(98, 1);
y = 1 + randi(98, 1);
Will that work for you? Then you can always be assured that a neighbor will be in the array. If not, then you've got a lot more checking to do to make sure the neighbor is not outside the array. Lots of ways but they all involve lots of if blocks or loops.
採用された回答
John D'Errico
2020 年 4 月 6 日
I would choose a random integer from 1 to 10000. We can use that as a linear index into the elements of your array, as if the array were unrolled into a vector. Since there are 100*100=10000 elements in total, this works.
Next, whatever the element is, which elements are adjacent to it? Thus up, down, right, left? For a 100x100 array, how would we find them? The trick is to understand how MATLAB stores elements in an array, and how that unrolled index works.
I'll do this for a fully general sized array, to make it more clear how things work. So assume an array of size nr by nc, thus nr rows and nc columns.
nr = 100;
nc = 100;
offset = [1 -1 nr -nr]; % down, up, right, left
% choose a random element in the matrix
randelem = randi(nr*nc,1);
% what are the neighbors of this element?
neighbor = randelem + offset;
% which of those neighors fall off the edge of the world?
[r,c] = ind2sub([nr,nc],neighbor);
neighbor((r < 1) | (c < 1) | (r > nr) | (c > nc)) = [];
% a random choice among one of those that remain
neighbor = neighbor(randi(numel(neighbor),1));
% convert back to row and column indices:
[r,c] = ind2sub([nr,nc],[randelem,neighbor]);
r
r =
55 56
c
c =
81 81
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Random Number Generation についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!