Error in using rmoutliers()
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Dear All,
I was read rmoutliers documentation carefully and want to use it in order to remove outliers' values in a matrix (namely FORCHECK). Actually I choose rmoutliers because rmoutliers detect outliers in each column or variable of A separately and removes the entire row.
Here is my code:
FFF = rmoutliers(FORCHECK,'percentiles',[0 90]);
I wanted to define outlier points as the point that is above the 90th percentile. But I got this error:
Error using matlab.internal.math.rmMissingOutliersVarargin>issueError
(line 137)
Dimension must be 1 or 2.
Error in matlab.internal.math.rmMissingOutliersVarargin>getDim (line
129)
issueError(funName,'DimensionInvalid');
Error in matlab.internal.math.rmMissingOutliersVarargin (line 47)
[opts,startNV] =
getDim(funName,opts,startNV,dimIn,numargs,doOutliers);
Error in matlab.internal.math.rmMissingOutliers>parseInputs (line 100)
opts =
matlab.internal.math.rmMissingOutliersVarargin(funName,A,opts,...
Error in matlab.internal.math.rmMissingOutliers (line 13)
opts = parseInputs(funName,A,varargin{:});
Error in rmoutliers (line 58)
[B,I] =
matlab.internal.math.rmMissingOutliers('rmoutliers',A,varargin{:});
How can I do?
0 件のコメント
採用された回答
Steven Lord
2020 年 4 月 1 日
The 'percentiles' option for rmoutliers, isoutlier, and filloutliers was introduced in release R2019a. You indicated you're using release R2018b, one release before that.
0 件のコメント
その他の回答 (1 件)
the cyclist
2020 年 4 月 1 日
Running this
load FORCHECK.mat
FFF = rmoutliers(FORCHECK,'percentiles',[0 90]);
worked just fine for me.
Maybe just restart MATLAB, in case you somehow have some other FORCHECK defined in your workspace?
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