function [ newMatrixA, newMatrixB ] = SwapLastColumns( matrixA, matrixB )
% SwapLastColumns: Exchange the last columns of input matrices
% matrixA and matrixB and return new matrices.
% Inputs: matrixA, matrixB - input matrices, must have same
% number of rows so columns can be swapped
%
% Outputs: newMatrixA, newMatrixB - returned new matrices created
% from input matrices with last
% columns swapped
% Assign tempColumn with last column matrixA
tempColumn = matrixA(:, end); % FIXME
% Assign newMatrixA with first columns of matrixA and last
% column of matrixB
newMatrixA = [matrixA(:,end-1), matrixB(:,end)]; % FIXME
% Assign newMatrixB with first columns of matrixB and last
% column of matrixA
newMatrixB = [matrixB(:,end-1), matrixA(:,end)]; % FIXME
end
As you can see above, I've written code that I thought would correctly swap the last columns between the two matrices, but it gives me an error. For my test cases, when swapping a 3x2 and a 3x2 matrix, the code works. But, when swapping a 3x3 and a 3x2 matrix it won't work, and outputs a 3x2 answer instead of a 3x3. Not quite sure what I'm doing wrong. Any help is appreciated.

 採用された回答

James Tursa
James Tursa 2020 年 3 月 31 日

1 投票

From your description, I don't see how your code works for anything other that inputs having two columns. I would guess that this
newMatrixA = [matrixA(:,end-1), matrixB(:,end)]; % FIXME
newMatrixB = [matrixB(:,end-1), matrixA(:,end)]; % FIXME
should be this to include all of the beginning columns
newMatrixA = [matrixA(:,1:end-1), matrixB(:,end)];
newMatrixB = [matrixB(:,1:end-1), matrixA(:,end)];

2 件のコメント

Kiernan King
Kiernan King 2020 年 3 月 31 日
That worked! Thanks so much
Dyuman Joshi
Dyuman Joshi 2024 年 3 月 28 日
Accepted as James's answer solves the problem posted.

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