Copy the value from a variable to a new name

Hi,

I have a not very difficult problem, but I don't know how to solve it. I've created a variable and I need to write this number (1, 2, 3 or 4) in the newfileName.

for k = 1:length(fileNames)
     n = num2str(fileNames{k}(3:4)); 
  if n > 20 & n < 21
      fileName = 1 % put your file name for this case here 
  elseif n >= 22 & n < 23
      fileName = 2 % put your file name for this case here 
  elseif n >= 24 & n < 25
      fileName = 3 % put your file name for this case here 
  else
      fileName = 4
  end

newFileName = [  fileNames{k}(3) '_dm_' fileNames{k}(4:9) '_' fileNames{k}(10:16) 'hu' ]; 

    movefile([myPath fileNames{k}], [myPath newFileName]);  
     end

For example, if I write the following code the result is not the value from this variable (1,2,3 or 4). It's "hufileName". How can I change it?

newFileName = [ fileNames{k}(3) '_dm_' fileNames{k}(4:9) '_' fileNames{k}(10:16) 'hu' 'fileName'

Thanks in advance and greetings,

Emma

Answer 1

[Robert Cumming]

in your code - filename is a number so you have two choices

1. use num2str to change it from a number to a string

     newFilename = [ 'string' num2str(filename) ];

2. make it expicitly a string

     filename = '1';

You may also benefit from looking up

help fullfile

[Emmanuelle]

Hi Robert, thanks for your quicky reply. I've tried with your steps but I always get an error at the movefile command. I've converted the number to a string doing this: S= {fileName} but now, when I runned the command 'movefile' I've received the following error: "??? Error using ==> movefile Argument must contain a string."

[Robert Cumming]

why are you putting it in a cell array? I didn't suggest that..

[Emmanuelle]

Sorry. I've tried this "n = ['string' num2str(fileNames{k}(4:9))];" and I get that error: ??? Error using ==> movefile. Also, when I change " fileName = '1';" I get the same error.

[Emmanuelle]

I've done something similar, as you said. Thank you so much Robert. Greetings,