ode45 is returning the incorrect solution

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Koren Murphy
Koren Murphy 2020 年 3 月 17 日
コメント済み: Ameer Hamza 2020 年 3 月 17 日
I am running an ode45 to solve a simple intergration. The intergration is so simple I can perform it by hand - hence knowing the solution returned is excessively large.
function [Output] = ContinuousFeed(t,u)
uA = u(1);
uB = u(2);
uE = u(3);
uF = u(4);
u = [uA; uB; uE; uF];
Output = u;
end
t=[0 10];
u0 = [1; 0.0002; 0; 0];
[t, u] = ode45 (@ContinuousFeed, t ,u0);
Why is it returning a final value of 22030.53 for the first column? All other columns are displaying inaccurate answers also.
Thank you!

採用された回答

Ameer Hamza
Ameer Hamza 2020 年 3 月 17 日
編集済み: Ameer Hamza 2020 年 3 月 17 日
The MATLAB is giving the correct solution. You are solving four independent ODEs of the form
which have an anatylical solution
The solution of ode45 matches this analytical solution.
  7 件のコメント
Koren Murphy
Koren Murphy 2020 年 3 月 17 日
I have applied this Steven and it has stopped the exponential. However, it appears to be adding the original feed to the solutions as it goes
function dudt = ContinuousFeed(~, ~);
ConstantVector = [1; 0.0002; 0; 0]; % initial conditions
dudt = ConstantVector;
end
r = 1e-6;
t = [0 10 10+r 20 20+r 30 30+r 40 40+r 50]; % this is assuming a sample taken every 10 units of time.
% tspan must constantly
% increase or decreases to
% work hence the addition of 1e-6
u0 = [1; 0.0002; 0; 0];
Therefore it is returning the solutions;
1
11
11.000001
21
21.000001
31
31.000001
41.
41.000001
51.
Ameer Hamza
Ameer Hamza 2020 年 3 月 17 日
If my initial feed you meant initial conditions, then this is the expected behavior. Vector u0 tells the ode45 where to start the solution of each variable.

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