How to simulate a random castle in a chessboard?

2 ビュー (過去 30 日間)
Osama Tabbakh
Osama Tabbakh 2020 年 2 月 16 日
コメント済み: Osama Tabbakh 2020 年 2 月 18 日
%the randomly generated castle should be within the chessboard, let say zeros matrix:
CB = zeros (8,8); % chessboard
% and the castle must be the one in this matrix:
C = 1; % Castle
% now randomly generate a castle:
CB (round((8-1)*rand+1),round((8-1)*rand+1))= C; % random generatation for castle
% then i will find out where is the generated castle and i want to generate also randomly a lot of castles, which are not in the same row and column:
[row,column] = find (CB);
x = round((8-1)*rand+1);
y = round((8-1)*rand+1);
I = length (row);
while row(I,:)~= x && row(I,:)~= y && column(I,:)~= y && column(I,:)~= x
CB (x,y)= C;
[row,column] = find (CB);
I = length (row);
x = round((8-1)*rand+1);
y = round((8-1)*rand+1);
end
disp (CB)
the problem is, i dont want to accept any number from row and column in the while loop. I tried with any, all and ismember (functions) but i is not working.
  2 件のコメント
Giuseppe Inghilterra
Giuseppe Inghilterra 2020 年 2 月 16 日
I don' understand well which is your problem.
Firstly, I advise you to use "randi" function, instead of round((8-1)*rand+1) (reference: https://www.mathworks.com/help/matlab/ref/randi.html) . In this way you generate random integer numbers.
Secondly, you could generate two random integer vectors:
x = randi(8,10,1); %this generates a vector of size [10,1] where each entry is within range [1,8].
y = randi(8,10,1);
CB(x,y) = C;
In this way CB matrix has value C=1 in 10 positions defined by pairs (x,y).
But, I don't understand what you want to do, i.e do you want to generate one random pair (x_i,y_i) per time and then if CB(x_i,y_i) is zero then you fill with 1 otherwise you stop while loop?
Osama Tabbakh
Osama Tabbakh 2020 年 2 月 16 日
yes, i want to fill the matrix (zeros) with 1 (one by one), but if one is in a position, the next one should not be in the same column and row.

サインインしてコメントする。

採用された回答

Giuseppe Inghilterra
Giuseppe Inghilterra 2020 年 2 月 17 日
Hi,
if you try to run this code:
close all
clear all
clc
n = 8; %chessboard size
CB = zeros(n,n); %init chessboard
k = 0;
niter = 0;
while(k<n) %stop condition
x = randi(n);
y = randi(n);
if sum(CB(x,:))+sum(CB(:,y)) == 0
CB(x,y) = 1;
k = k+1;
end
niter = niter + 1;
end
spy(CB,'ro',28)
hold on
spy(~CB,'b+',28)
you fill with 1 if there are no ones in the same row or column, obtaining following result (this plot changes every time due to introduced randomness with randi function):
Hope this helps.
  1 件のコメント
Osama Tabbakh
Osama Tabbakh 2020 年 2 月 18 日
Thanks, it is working

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeRandom Number Generation についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by