Make .wav signals same size?
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Djordje Damnjanovic
2020 年 2 月 14 日
コメント済み: Djordje Damnjanovic
2020 年 2 月 19 日
Hello everyone!
I have this problem. I need to read for example 60 wav signals, find the shortest one and cut all of them to the size of shortest.
Process of cut is like this: from the middle of the signal need to cut signal right and left equally to the size of shortest signal.
I upload picture as extra explanation.
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Image Analyst
2020 年 2 月 14 日
See the FAQ: How_can_I_process_a_sequence_of_files?
The "dir()" version of the code is probably what you want. So do the loop once to scan the files, calling audioread, then get the length, then scan again to do the cropping. Make sure you save into a different folder so you don't permanently destroy your input sound files. In short:
filePattern = fullfile(inputFolder, '*.wav');
files = dir(filePattern)
minLength = inf;
for k = 1 : length(files)
thisFileName = fullfile(inputFolder, files(k).name);
[y, fs] = audioread(thisFileName);
if length(y) > minLength
maxLength = length(y);
end
end
% Now scan again, doing the cropping
for k = 1 : length(files)
thisFileName = fullfile(inputFolder, files(k).name);
[y, fs] = audioread(thisFileName);
y = y(1:minLength);
outputFileName = fullfile(outputFolder, files(k).name);
audiowrite(...........
end
etc. Or something like that. Of course you need to assign inputFolder and outputFolder to some actual folders on your drive.
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